⇒cos(22π−A)+cos(22π+B)+cos(22π+C)−sin(2π+D)
→−cosA−cosB−cosC−cosD
→−cos(22π−B)−cosB−cos(22π−D)−cosD
→cosB−cosB+cosD−cosD
→0Proved.
By: Dipankar Sadhukhan.