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Ramanujan paradox

S1=11+11+11+1...=0[if ,n=even]

S1=0+11+11+11+...=1[if n=odd]

now add (i) and (ii)

2S1=1

S1=21

S2=12+34+56+...

S2=0+12+34+5...

nowadd(iii)and(iv)2S2=11+11+1...2S2=S1=21S2=41S3=1+2+3+4+5+...S2=12+34+5...S3S2=0+40+80+160+20...S341=4(1+2+3+4+5+...)4S3S3=41S3=1211+2+3+4+5+...=121